please note the following corrections in the video.
1. Design of Subnet1:
The Last address in the first subnet is 14.24.74.127 and not 14.24.74.128 as we know that the decimal value of 01111111
is 127.
2. Design of Subnet2:
First address in the second subnet is 14.24.74.128 and not 14.24.74.129
Binary value of 128(01111111) has to be taken in the last octet and not of 129(10000001)to determine the last address in
the second subnet.
10111111 is the binary value for 191. The last address in the second subnet is 14.24.74.191.