Day 61: Sorting an Array in Ascending Order | 100 Days of JavaScript Coding Challenge 🎯

Опубликовано: 14 Январь 2025
на канале: Code with Poonam

103

Welcome to Day 61 of the 100 Days of JavaScript Coding Challenge! 🚀
#codewithpoonam #100DaysOfCode

🛠️ Challenge Question
Write a JavaScript function sortArray() to sort an array in ascending order without using any inbuilt methods.

Example Input and Output:

Input:
[6, 1, 5, 2, 4, 3]
Output:
[1, 2, 3, 4, 5, 6]

Input:
[56, 90, 2, 13]
Output:
[2, 13, 56, 90]

💡 Solution Approach

Key Steps:
1️⃣ Nested Loop for Comparison:
Use two loops: the outer loop (i) to fix the position, and the inner loop (j) to compare elements.

2️⃣ Comparison Logic:
Compare the elements at positions i and j.
If arr[i] greater than arr[j], swap the elements to place the smaller one at i.

3️⃣ Swapping Values:
Use a temporary variable to swap the values of arr[i] and arr[j].

🔑 Key Concepts Covered:
Nested Loops: Learn to iterate through an array using nested for loops.
Manual Sorting: Implement sorting logic without built-in functions.
Swapping Values: Use temporary variables for value swapping.

🌟 Test Scenarios:
✅ Arrays with positive numbers.
✅ Arrays with negative numbers.
✅ Arrays with a mix of positive and negative numbers.
✅ Single-element arrays.
✅ Empty arrays (edge case).

🔥 Keep Progressing! 🎯
With Day 61, you’ve mastered how to sort an array manually, strengthening your understanding of sorting algorithms and array manipulation. 🚀

#javascript #SortingArrays #Day61 #ManualSorting #NestedLoops #codechallenge

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